介绍
视频地址:www.bilibili.com/video/av78062009/
相关源码:github.com/anonymousGiga/Rust-link...
详细内容
本节我们实现可持久化链表的Drop。我们在之前实现可变链表的Drop的时候,我们是使用循环来进行回收的。这里我们如果采用统一的方法,是行不通的,因为我们此处通过Rc进行共享,必须等待引用计数为0 才能将数据从Rc中移除。
Drop的实现
Drop实现如下:
//实现Drop
impl<T> Drop for List<T> {
fn drop(&mut self) {let mut head = self.head.take();
while let Some(node) = head {if let Ok(mut node) = Rc::try_unwrap(node) {
head = node.next.take();} else {break;}}}
}
完整代码如下:
use std::rc::Rc;
pub struct List<T> {
head: Link<T>,
}
type Link<T> = Option<Rc<Node<T>>>;
struct Node<T> {
elem: T,
next: Link<T>,
}
impl<T> List<T> {
pub fn new() -> Self {
List { head: None }}
pub fn append(&mut self, elem: T) -> List<T> {
List { head: Some(Rc::new(Node {
elem: elem,
next: self.head.clone(),}))}
}
pub fn tail(&self) -> List<T> {
List { head: self.head.as_ref().and_then(|node| {
node.next.clone()})}}
pub fn head(&self) -> Option<&T> {
self.head.as_ref().map(|node| &node.elem)}
}
//实现Iter
pub struct Iter<'a, T> {
next: Option<&'a Node<T>>,
}
impl<T> List<T> {
pub fn iter(&self) -> Iter<T> {
Iter { next: self.head.as_deref() }}
}
impl<'a, T> Iterator for Iter<'a, T> {
type Item = &'a T;
fn next(&mut self) -> Option<Self::Item> {
self.next.map(|node| {
self.next = node.next.as_deref();&node.elem
})}
}
//实现Drop
impl<T> Drop for List<T> {
fn drop(&mut self) {let mut head = self.head.take();
while let Some(node) = head {if let Ok(mut node) = Rc::try_unwrap(node) {
head = node.next.take();} else {break;}}}
}
#[cfg(test)]
mod test {
use super::List;
#[test]
fn basics() {let mut list = List::new();
assert_eq!(list.head(), None);
let list = list.append(1).append(2).append(3);
assert_eq!(list.head(), Some(&3));
let list = list.tail();
assert_eq!(list.head(), Some(&2));
let list = list.tail();
assert_eq!(list.head(), Some(&1));
let list = list.tail();
assert_eq!(list.head(), None);}
#[test]
fn iter() {let list = List::new().append(1).append(2).append(3);let mut iter = list.iter();
assert_eq!(iter.next(), Some(&3));
assert_eq!(iter.next(), Some(&2));
assert_eq!(iter.next(), Some(&1));}
}